4x+2^2=28

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Solution for 4x+2^2=28 equation: 



4x+2^2=28

We move all terms to the left:

4x+2^2-(28)=0

determiningTheFunctionDomain
4x-28+2^2=0

We add all the numbers together, and all the variables

4x-24=0

We move all terms containing x to the left, all other terms to the right

4x=24

x=24/4

x=6

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